Question

A conductor with rectangular cross section has dimensions $(a\times 2a\times 4a)$ as shown in figure. Resistance across AB is 'x', across CD is 'y' and across EF is 'z'. Then

• A. x = y = z
• B. x > y > z
• C. y > z > x
• D. x > z > y

Answer 1

The correct option is D x > z > y

$R=\frac{\rho l}{A}$
$R\propto \frac{1}{A}$
Area of AB =$2a^2$
Area of CD = $8a^2$
Area of EF = $4a^2$
So, x > z >y