A conical and a hemispherical solid of the same height and radius are to be attached at both ends of a solid cylindrical metallic block whose radius is the same as that of the other solids. The height of the new solid so formed is ³/₂ times the height of the cylindrical block. is the radius of the hemisphere.

What is the difference between the total surface areas of the new solid and the cylindrical block?

πr²

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√2πr²

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2πr²

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(2 + √2)πr²

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Solution

The correct option is B
√2πr²

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The correct option is B √2πr2

The correct option is B
√2πr²