A conical water tank has a radius of $0.2$ mm and height of $1.2$ mm, find total surface area of the tank.

0.9734 c m

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0.9734 {c m}^{2}

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0.9734 m m

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0.9734 {m m}^{2}

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Solution

The correct option is D $0.9734 {m m}^{2}$
Given, radius $r = 0.2$ mm and height $h = 1.2$ mm .

Then, slant height is:
$⟹$ $s^{2} = h^{2} + r^{2}$
$⟹$ $s^{2} = {1.2}^{2} + {0.2}^{2}$
$⟹$ $s^{2} = 1.44 + 0.4$
$⟹$ $s = \sqrt{(1.84)}$
$⟹$ $s = 1.35$ mm.

So, surface area of a cone $= π r s + π r^{2}$
$= 3.14 \times 0.2 \times 1.35 + 3.14 \times 0.2 \times 0.2$
$= 0.8478 + 0.1256$
$= 0.9734 {m m}^{2}$ .

Therefore, option $D$ is correct.

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A conical water tank has a radius of 0.2 mm and height of 1.2 mm, find total surface area of the tank.

The correct option is D 0.9734 mm2Given, radius r=0.2 mm and height h=1.2 mm .Then, slant height is:⟹ s2=h2+r2⟹ s2=1.22+0.22⟹ s2=1.44+0.4⟹ s=√(1.84)⟹ s=1.35 mm.So, surface area of a cone =πrs+πr2=3.14×0.2×1.35+3.14×0.2×0.2=0.8478+0.1256=0.9734 mm2.Therefore, option D is correct.

A conical water tank has a radius of $0.2$ mm and height of $1.2$ mm, find total surface area of the tank.