A constable follows a thief who is 200m ahead of the constable If the constable and the thief runs at the speeds of 8 km/hr and 7 km/hr respectively the constable would catch the thief in

10 min

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12 min

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15 min

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20 min

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Solution

The correct option is A 12 min
Relative speed = (8 - 7) = 1 km/hr
( $∵$ Both are in the same direction)
= $1 \times \frac{5}{18} = \frac{5}{18} m / s e c$

$∴$ Required time = $\frac{200}{\frac{5}{18}} = \frac{200 \times 18}{5}$ seconds = 720 seconds = 12 min.

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A constable follows a thief who is 200m ahead of the constable If the constable and the thief runs at the speeds of 8 km/hr and 7 km/hr respectively the constable would catch the thief in

The correct option is A 12 minRelative speed = (8 - 7) = 1 km/hr(∵ Both are in the same direction) = 1×518=518m/sec∴ Required time = 200518=200×185 seconds = 720 seconds = 12 min.

The correct option is A 12 min
Relative speed = (8 - 7) = 1 km/hr
( $∵$ Both are in the same direction)
= $1 \times \frac{5}{18} = \frac{5}{18} m / s e c$

$∴$ Required time = $\frac{200}{\frac{5}{18}} = \frac{200 \times 18}{5}$ seconds = 720 seconds = 12 min.