A thief is running at a speed of $6$ km per hour and a police constable is chasing him with a speed of $8$ km per hour. If originally, the distance between the thief and the constable is $500$ m. After what distance, will the constable catch the thief ?

0.7

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1.5

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0.9

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1.6

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Solution

The correct option is B $1.5$ km
We know, $500$ m $= 0.5$ km
The police is gaining on the thief at $2$ km/hr i.e. $(8 - 6)$ .
Time to catch $= \frac{0.5}{2} = 0.25$ hours.
The police travels $2$ km $(8 \times 0.25)$
The thief travels $1.5$ km $(6 \times 0.25)$ .

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A thief is running at a speed of 6 km per hour and a police constable is chasing him with a speed of 8 km per hour. If originally, the distance between the thief and the constable is 500 m. After what distance, will the constable catch the thief ?

The correct option is B 1.5 kmWe know, 500 m =0.5 kmThe police is gaining on the thief at 2 km/hr i.e. (8−6).Time to catch =0.52=0.25 hours.The police travels 2 km (8×0.25)The thief travels 1.5 km (6×0.25).

A thief is running at a speed of $6$ km per hour and a police constable is chasing him with a speed of $8$ km per hour. If originally, the distance between the thief and the constable is $500$ m. After what distance, will the constable catch the thief ?

The correct option is B $1.5$ km
We know, $500$ m $= 0.5$ km
The police is gaining on the thief at $2$ km/hr i.e. $(8 - 6)$ .
Time to catch $= \frac{0.5}{2} = 0.25$ hours.
The police travels $2$ km $(8 \times 0.25)$
The thief travels $1.5$ km $(6 \times 0.25)$ .