Question

A constant force acts on an object of mass 5kg for duration of 2s. It increases the object velocity from 3m/s to 7m/s. Find the magnitude of applied force. Now if the force was applied for the duration of 5s what would be the final velocity of the object

Answer 1

Let the force be F,
Mass is M,
time for which it is accelerated = 2s
velocity is increased from 3m/s to 7m/s
so, acceleration is , a = (7-3)/2 = 2m/s²
The force applied is, F = ma = (5)(2) = 10 N
Now, the force is applied for 5s, the velocity after 5s will be,
v=u+at
=> v =3+(2)(5)
=>v=13m/s , this is final velocity.