A constant force →F=3^i+2^j+4^k is applied at the point (1,0,1), then the vector moment of →F about the point (1,2,3) is
A
4^i+6^j−6^k
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B
4^i−6^j−6^k
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C
6^i−4^j+6^k
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D
−6^i−4^j+6^k
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Solution
The correct option is A4^i+6^j−6^k The vector moment of a force about a point is given by →r×→F where →r is the vector from the point of application of force to the point about which moment is being taken.
→r=2^j+2^k
Moment =(2^j+2^k)×(3^i+2^j+4^k) =−6^k+8^i+6^j−4^i =4^i+6^j−6^k