A constant force, $\to F = 2^i + 2^j$ acts on a body of mass 2 kg due to which the body gets displaced from (0,0,0) to (5,0,0). What is the work done by this force?

-10 J

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10 J

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15 J

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-15 J

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Solution

The correct option is B
10 J

The component of force along the displacement is only needed for calculating its work done.
Here, $\to F = 2^i + 2^j$
m = 2kg
$\to s = 5^i$
W = $\to F . \to s = (2^i + 3^j) . (5^i)$
= 10 J

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Similar questions

Q. A force,

\to F = 2^i + 2^j

acts on a 2 kg body which got displaced from (0,0,0) to (5,0,0). The work done by this force is .

A constant force, $\to F = 2^i + 2^j$ acts on a body of mass 2 kg due to which the body gets displaced from (0,0,0) to (5,0,0). What is the work done by this force?

Q. A force,

\to F = 2^i + 2^j

acts on a 2 kg body which got displaced from (0,0,0) to (5,0,0). The work done by this force is .

A

force

\to F = 2^i + 4^j +^k

acts on a body and produces a displacement of

\to S = 3^i + 2^j + 5^k

. Work done is:

Q. If

\to F = 2^i + 3^j + 4^k

acts on a body and displaces it by

\to S = 3^i + 2^j + 5^k

, then the work done by the force is:

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A constant force,→F=2^i+2^j acts on a body of mass 2 kg due to which the body gets displaced from (0,0,0) to (5,0,0). What is the work done by this force?

The correct option is B 10 J The component of force along the displacement is only needed for calculating its work done. Here, →F=2^i+2^j m = 2kg →s=5^i W = →F.→s=(2^i+3^j).(5^i) = 10 J

A constant force, $\to F = 2^i + 2^j$ acts on a body of mass 2 kg due to which the body gets displaced from (0,0,0) to (5,0,0). What is the work done by this force?

The correct option is B
10 J

The component of force along the displacement is only needed for calculating its work done.
Here, $\to F = 2^i + 2^j$
m = 2kg
$\to s = 5^i$
W = $\to F . \to s = (2^i + 3^j) . (5^i)$
= 10 J