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Question

A constant force,F=2^i+2^j acts on a body of mass 2 kg due to which the body gets displaced from (0,0,0) to (5,0,0). What is the work done by this force?


A

-10 J

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B

10 J

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C
15 J
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D
-15 J
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Solution

The correct option is B

10 J


The component of force along the displacement is only needed for calculating its work done.
Here, F=2^i+2^j
m = 2kg
s=5^i
W = F.s=(2^i+3^j).(5^i)
= 10 J

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