A constant force,→F=2^i+2^j acts on a body of mass 2 kg due to which the body gets displaced from (0,0,0) to (5,0,0). What is the work done by this force?
A
-10 J
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B
10 J
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C
15 J
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D
-15 J
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Solution
The correct option is B
10 J
The component of force along the displacement is only needed for calculating its work done.
Here, →F=2^i+2^j
m = 2kg →s=5^i
W = →F.→s=(2^i+3^j).(5^i)
= 10 J