A container contains $40$ litres of milk. From this container $4$ litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

26.34

litres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

27.36

litres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

28

litres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

29.16

litres

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $29.16$ litres
Amount of milk left after $3$ operations $= [40 {(1 - \frac{4}{40})}^{3}]$ litres
$= (40 \times \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10}) = 29.16$ litres.

Suggest Corrections

Similar questions

80 litres of milk is kept in a container. From this volume, 8 litres of milk was taken out and replaced by water. This process was repeated two more times. How much milk (approximately) is now present in the container?

Q. A container has

60

litres of milk. From this container

6

litres of milk was taken out and replaced by water.The process was further repeated twice. The volume of milk in the container after that is _________

Q. From a container of milk,

5

litres of milk is replaced with

5

litres of water. This process is repeated again. Thus in two attempts the ratio of milk and water became

81 : 19.

The initial amount of milk in the container was

Q. A flask holds 30 litres of curd. From this flask 3 litres of curd were taken out and traded by water. This process was repeated further two times. How much curd is now contained in the flask?

Q. From a container 6 litres milk was drawn out and was replaced by water. Again 6 litres of mixture was drawn out and replaced by water. Thus the quantity of milk in the container after these two operations is 9: 16. Calculate the quantity of the milk initially in the container:

Join BYJU'S Learning Program

A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

The correct option is C 29.16 litresAmount of milk left after 3 operations =[40(1−440)3] litres=(40×910×910×910)=29.16 litres.

A container contains $40$ litres of milk. From this container $4$ litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

The correct option is C $29.16$ litres
Amount of milk left after $3$ operations $= [40 {(1 - \frac{4}{40})}^{3}]$ litres
$= (40 \times \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10}) = 29.16$ litres.