Question

A container of $1L$ capacity contains a mixture of $4g$ of $O_2$ and $2g$ of $H_2$ at $0^{\circ }C$. What will be the total pressure of the mixture?

• A. $50.42atm$
• B. $25.21atm$
• C. $15.2atm$
• D. $12.5atm$

Answer 1

The correct option is B $25.21atm$

Applying $PV=\frac{w}{M}RT$
$p_{O_2}=\frac{4}{32}\times \frac{0.0821\times 273}{1}=2.81atm$
$p_{H_2}=\frac{2}{2}\times \frac{0.0821\times 273}{1}=22.4atm$
$p_{total}=p_{O_2}+p_{H_2}=2.81+22.4=25.21atm$.