A container of volume 2.24 L can withstand a maximum pressure of 2 atm at 298 K before exploding. The maximum amount of nitrogen (in g) that can be safely put in this container at this temperature is closest to
A
2.8
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B
5.1
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C
1.4
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D
4.2
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Solution
The correct option is B 5.1 IdealgasequationPV=nRTMolesofN2gas(n)=PVRT=2atm×2.24L0.821Latmmol−1K−1×298Kn=4.480.082×298MassofN2gas(ing)=moles×molarMass=4.48×280.0821×298=5.1g