A container when is empty weighs $50 g m$ . After certain liquid of density $25 g m / d m^{3}$ is filled its mass becomes equal to $100 g m$ . The volume of the container will be:

0.25 d m^{3}

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0.5 d m^{3}

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1 d m^{3}

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2 d m^{3}

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Solution

The correct option is A $2 d m^{3}$
Weight of the contents = Filled Weight - Empty Weight
= 100 - 50 g
= 50 g
Volume of the container = $\frac{50}{25} {d m}^{3}$
= 2 ${d m}^{3}$

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A container when is empty weighs 50gm. After certain liquid of density 25gm/dm3 is filled its mass becomes equal to 100gm. The volume of the container will be:

The correct option is A 2dm3Weight of the contents = Filled Weight - Empty Weight = 100 - 50 g = 50 g Volume of the container = 5025dm3 = 2 dm3

A container when is empty weighs $50 g m$ . After certain liquid of density $25 g m / d m^{3}$ is filled its mass becomes equal to $100 g m$ . The volume of the container will be:

The correct option is A $2 d m^{3}$
Weight of the contents = Filled Weight - Empty Weight
= 100 - 50 g
= 50 g
Volume of the container = $\frac{50}{25} {d m}^{3}$
= 2 ${d m}^{3}$