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Question

A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 °C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g–1 K–1; heat of fusion of water = 335 J g–1).

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Solution

Mass of the copper block, m = 2.5 kg = 2500 g

Rise in the temperature of the copper block, Δθ = 500°C

Specific heat of copper, C = 0.39 J g–1 °C–1

Heat of fusion of water, L = 335 J g–1

The maximum heat the copper block can lose, Q = mCΔθ

= 2500 × 0.39 × 500

= 487500 J

Let m1 g be the amount of ice that melts when the copper block is placed on the ice block.

The heat gained by the melted ice, Q = m1L

Hence, the maximum amount of ice that can melt is 1.45 kg.


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