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Question

A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500°C and then placed on a large ice block. What is the maximum amount of ice that can melt? (specific heat of copper= 0.39jg1k1 ; heat of fusion of water = 335jg-1)


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Solution

Step 1: Given data

Mass of copper = 2.5kg

Rise is temperature = 500°C

Specific heat of copper= 0.39jg1k1

The heat of fusion of water = 335jg-1

Step 2: Calculating heat lost by copper

The amount of heat lost by the copper block is

Q=mCTQ=2.5×1000×.39×500Q=2500×195Q=487500J

Step 3: Calculating amount of ice that can melt

Let us assume that the amount of ice that can melt be m1gwhen the copper is placed on the ice block

The amount of heat gained by the melted ice is Q=m1L

Q=m1Lm1=QLm1=487500335m1=1455.223gm1=1.45kg

Therefore, the maximum amount of ice that can melt is 1.45kg.


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