A copper block of mass 50 g is heated to 100- and placed on a block of ice at 0- C- The specific heat of copper is 0-1 cal g-1 - C-1 and latent heat of ice is 80 cal g-1- The amount of ice melted is

The correct option is C 6.25 gCopper block m=50g, L=80^cecal g^ 1 T=100^0C S=0· 1 cal g^ 1c^ 1 50× 100× 0· 1=80× m m=50× 100× 0· 1/80=6· ...

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Byju's Answer

Standard X

Physics

Power

A copper bloc...

Question

A copper block of mass 50 g is heated to $100^{\circ}$ and placed on a block of ice at $0^{\circ} C$ . The specific heat of copper is 0.1 cal $g^{- 1}$ $^{\circ} C^{- 1}$ and latent heat of ice is $80 c a l g^{- 1}$ . The amount of ice melted is

6.15 g

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6.2 g

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6.25 g

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6.3 g

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Solution

The correct option is C 6.25 g
Copper block
$m = 50 g, L = 80^{c e} c a l g^{- 1}$
$T = 100^{0} C$
$S = 0 \cdot 1 c a l g^{- 1} c^{- 1}$
$50 \times 100 \times 0 \cdot 1 = 80 \times m$
$m = \frac{50 \times 100 \times 0 \cdot 1}{80} = 6 \cdot 25 g$

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A copper block of mass 50 g is heated to 100∘ and placed on a block of ice at 0∘C. The specific heat of copper is 0.1 cal g−1 ∘C−1 and latent heat of ice is 80calg−1. The amount of ice melted is

The correct option is C 6.25 gCopper blockm=50g,L=80cecalg−1T=1000CS=0⋅1calg−1c−150×100×0⋅1=80×mm=50×100×0⋅180=6⋅25g

A copper block of mass 50 g is heated to $100^{\circ}$ and placed on a block of ice at $0^{\circ} C$ . The specific heat of copper is 0.1 cal $g^{- 1}$ $^{\circ} C^{- 1}$ and latent heat of ice is $80 c a l g^{- 1}$ . The amount of ice melted is

The correct option is C 6.25 g
Copper block
$m = 50 g, L = 80^{c e} c a l g^{- 1}$
$T = 100^{0} C$
$S = 0 \cdot 1 c a l g^{- 1} c^{- 1}$
$50 \times 100 \times 0 \cdot 1 = 80 \times m$
$m = \frac{50 \times 100 \times 0 \cdot 1}{80} = 6 \cdot 25 g$