A copper disc of radius $0.1$ m is rotated about its center with $20$ revolution per second in a uniform magnetic field of $0.1$ T with its plane perpendicular to the field. The emf induced across the radius of the disc is?

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Solution

Emf induced is given by $= \frac{1}{2} B ω R^{2}$ ---(1) where B=magnetic field=0.1T; $ω$ =angular velocity=20 revolution per second and R=radius of the disc=0.1 m
Now putting the above mentioned values in equation 1
emf $= \frac{1}{2} 0.1 \times 2 π \times 20 \times (0.1)^{2} = 0.0628$

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A copper disc of radius 0.1m is rotated about its center with 20 revolution per second in a uniform magnetic field of 0.1T with its plane perpendicular to the field. The emf induced across the radius of the disc is?

Emf induced is given by=12BωR2---(1) where B=magnetic field=0.1T; ω=angular velocity=20 revolution per second and R=radius of the disc=0.1 mNow putting the above mentioned values in equation 1 emf=120.1×2π×20×(0.1)2=0.0628

A copper disc of radius $0.1$ m is rotated about its center with $20$ revolution per second in a uniform magnetic field of $0.1$ T with its plane perpendicular to the field. The emf induced across the radius of the disc is?

Emf induced is given by $= \frac{1}{2} B ω R^{2}$ ---(1) where B=magnetic field=0.1T; $ω$ =angular velocity=20 revolution per second and R=radius of the disc=0.1 m
Now putting the above mentioned values in equation 1
emf $= \frac{1}{2} 0.1 \times 2 π \times 20 \times (0.1)^{2} = 0.0628$