You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Rotational EMF

A copper disc...

Question

A copper disc or radius 0.1 m rotates about its axis in a uniform magnetic field of 0.1. Tesla at 10 rotations per second. the plane of the disc remains normal to the magnetic field. The induced emf along the radius of the disc will be

\frac{π}{10} v o l t

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 π}{10} v o l t

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{100} v o l t

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 π v o l t

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{π}{100} v o l t$
$e m f = \int_{0}^{R} B r ω d r$
$= \frac{B ω R^{2}}{2}$
$= 0.1 \times 2 π 10 \times \frac{{0.1}^{2}}{2}$
$= \frac{π}{100} V$

Suggest Corrections

Similar questions

A copper disc of radius 0.1 m rotates about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla. The emf induced across the radius of the disc is

Q. A copper disc of radius 0.1 m rotates about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla. The emf induced across the radius of the disc is

Q. A copper disc of radius

0.1

m

rotated about its centre with

10

revolutions per second in a uniform magnetic field of

0.1

tesla with it's plane perpendicular to the field. The e.m.f. induced across the radius of disc is:

Q. A copper disc of radius

0.1 m

is rotated about its centre at

20

revolutions per second in a uniform magnetic field of

0.1 T

with its plane perpendicular to the field. The emf induced across the radius of the disc is -

Q. A copper disc of radius

0.1

m is rotated about its center with

20

revolution per second in a uniform magnetic field of

0.1

T with its plane perpendicular to the field. The emf induced across the radius of the disc is?

Join BYJU'S Learning Program

A copper disc or radius 0.1 m rotates about its axis in a uniform magnetic field of 0.1. Tesla at 10 rotations per second. the plane of the disc remains normal to the magnetic field. The induced emf along the radius of the disc will be

The correct option is B π100voltemf=∫R0Brωdr=BωR22=0.1×2π10×0.122=π100V

The correct option is B $\frac{π}{100} v o l t$
$e m f = \int_{0}^{R} B r ω d r$
$= \frac{B ω R^{2}}{2}$
$= 0.1 \times 2 π 10 \times \frac{{0.1}^{2}}{2}$
$= \frac{π}{100} V$