Let the number of toys produced on that day be x.
∴ The cost of production (in rupees) of each toy that day = 55–x
So, the total cost of production (in rupees) that day = x×(55−x) [.5 Mark]
∴ x×(55−x)=750
⇒ 55(x) – x2=750
⇒ −x2 + 55x–750=0
⇒ x2 – 55x+750=0 [.5 Mark]
∴ The number of toys produced that day satisfies the quadratic equation
x2 – 55x+750=0 which is the required representation of the problem mathematically.
[1 Mark]