A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of articles produced in a day. On a particular day, the total cost of production was Rs. 750. If x denotes the number of toys produced that day, form the quadratic equation of find x.
As per question, the number of toys produced on that day be x.
∴ The cost of production (in rupees) of each toy on that day = 55–x
So, the total cost of production (in rupees) that day = x×(55−x)
∴ x(55−x)=750
⇒ 55x–x2=750
⇒ −x2+55x–750=0
⇒ x2–55x+750=0
∴ The number of toys produced that day satisfies the quadratic equation.
x2–55x+750=0 which is the required representation of the problem mathematically.