Question

Question 23

A covered wooden box has the inner measures as 115 cm, 75 cm and 35 and thickness of wood as 2.5. cm. The volume of the wood is
(a) $85000c{m}^3$ (b) $80000c{m}^3$
(c) $82125c{m}^3$ (d) $84000c{m}^3$

Answer 1

Given, inner measures of a wooden box as 115 cm, 75 cm and 35 cm.
Since, thickness of the box is 2.5 cm, then outer measures will be 115 + 5, 75 + 5 and 35 + 5, i.e. 120 cm, 80 cm and 40 cm.
$\therefore$ The outer volume $=120\times 80\times 40=384000c{m}^3$
and the inner volume $=115\times 75\times 35=301875c{m}^3$ $[\because$ volume of cuboid $=l\times b\times h$]
$\therefore$ Volume of the wood = Outer volume - Inner volume
$=384000-301875=82125c{m}^3$