A covered wooden box has the inner measures as $115 c m, 75 c m$ and $35 c m$ and the thickness of wood is $2.5 c m$ . The volume of the wood is :

81000 c u . c m

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81775 c u . c m

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82125 c u . c m

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Solution

The correct option is C $82125 c u . c m$
Inner volume of the box $= 115 \times 75 \times 35 = 301875 {c m}^{3}$
Outer volume of the box $= (115 + 5) \times (75 + 5) \times (35 + 5) = 120 \times 80 \times 40 = 384000 {c m}^{3}$
Therefore,
Volume of the wood $=$ Outer volume $-$ Inner volume
$\Rightarrow$ Volume of the wood $= 384000 - 301875 = 82125 {c m}^{3}$

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A covered wooden box has the inner measures as 115 cm, 75 cm and 35 and thickness of wood as 2.5. cm. The volume of the wood is
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(c) $82125 c m^{3}$ (d) $84000 c m^{3}$

Q. A covered wooden box has the inner measures as

115

cm,

75

cm,

35

cm and the thickness of wood is

2.5

cm. Then the volume of the wood is ___________.

Q. A covered wooden box has the inner measures as 115 cm, 75 cm and 35 and thickness of wood as 2.5. cm. The volume of the wood is
(a)

85, 000 c m^{3}

(b)

80, 000 c m^{3}

(c)

82, 125 c m^{3}

(d)

84, 000 c m^{3}

Q. A wooden box measures

20

cm by

10

cm by

9

cm Thickness of wood is 1 cm Volume of wood to make the box ( in cubic cm) is:

Q. A closed box is made of 2 cm thick wood with dimensions 84 cm × 75 cm × 64 cm. Find the volume of the wood required to make the box.

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A covered wooden box has the inner measures as 115 cm,75 cm and 35 cm and the thickness of wood is 2.5 cm. The volume of the wood is :

The correct option is C 82125 cu. cmInner volume of the box =115×75×35=301875cm3Outer volume of the box =(115+5)×(75+5)×(35+5)=120×80×40=384000cm3Therefore,Volume of the wood = Outer volume −Inner volume⇒ Volume of the wood =384000−301875=82125cm3

A covered wooden box has the inner measures as $115 c m, 75 c m$ and $35 c m$ and the thickness of wood is $2.5 c m$ . The volume of the wood is :