Question

A covered wooden box has the inner measures as 115 cm, 75 cm and 35 and thickness of wood as 2.5. cm. The volume of the wood is
(a) $85,000c{m}^3$ (b) $80,000c{m}^3$
(c) $82,125c{m}^3$ (d) $84,000c{m}^3$

Answer 1

Given, the inner measures of a wooden box as 115 cm, 75 cm and 35 cm.
Since, the thickness of the box is 2.5 cm, then outer measures will be (115 + 5) cm, (75 + 5) cm and (35 + 5) cm, i.e. 120 cm, 80 cm and 40 cm.
$\therefore$ The outer volume $=120\times 80\times 40=3,84,000c{m}^3$
and the inner volume $=115\times 75\times 35=3,01,875c{m}^3$
$[\because$ volume of cuboid $=l\times b\times h$]
$\therefore$ Volume of the wood = Outer volume - Inner volume
$=3,84,000-3,01,875=82,125c{m}^3$