A cricket ball of mass $0.25 k g$ with speed $10 m / s$ collides with a bat and returns with same speed within $0.01 s$ . The force acted on bat is (in $N$ ):

25

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50

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250

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500

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Solution

The correct option is D $500$
Velocity of cricket ball initially $u = 10^i m / s$
Velocity of cricket ball finally $v = - 10^i m / s$
Mass of ball $m = 0.25 k g$
Change in momentum of the ball $Δ p = m (v - u) = (0.25) (- 10 - 10)^i = - 5^i k g m / s$
Magnitude of change in momentum $| Δ p | = 5 k g m / s$
Force acting on the bat $F = \frac{Δ p}{Δ t} = \frac{5}{0.01} = 500 N$

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A cricket ball of mass 0.25kg with speed 10m/s collides with a bat and returns with same speed within 0.01s. The force acted on bat is (in N):

A cricket ball of mass $0.25 k g$ with speed $10 m / s$ collides with a bat and returns with same speed within $0.01 s$ . The force acted on bat is (in $N$ ):