A cross between yellow flowered and round fruit (both dominant) bearing plant and white flowered elongated fruit (both recessive) bearing plant yielded 20 plants in $F_{1}$ progeny which formed 960 plants in $F_{2}$ generation. The number of plants with yellow flowers and round fruits in $F_{1}$ and $F_{2}$ generations would be

20, 960

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20, 540

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10, 180

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10, 60.

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Solution

The correct option is B 20, 540
class=A cross is made between pure yellow flowered and round fruit(YYRR) with white flowered elongated fruit(yyrr). In the F1 generation 20 progeny with yellow flowered and round fruits(YyRr) are formed. When they are subjected to self pollination followed by self fertilization, in the F2 generation, 960 progeny are formed. In these 540 plants are yellow flowered round fruits, plants are yellow flowered elongated fruits, 180 fruits are white flowered round fruits and 60 plants are white flowered elongated fruits the correct option is 20, 540

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