A cube of mass $5 k g$ with each side $2 c m$ is lying on the table. Find the pressure exerted by the cube on the table.

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Solution

$\begin{matrix} P = \frac{F}{A} = \frac{m g}{a r e a} = \frac{5 \times 10 \times 100 \times 100}{2 \times 2} = 125, 00 p a \end{matrix}$

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A cube of mass 1kg with each side of 1cm is lying on the table. find the pressure exerted by the block on the table. Take g = 10 $m / s^{2}$ .

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