Question

The pressure exerted on a table, when a cube of side 10 cm and mass 5 kg is kept on it, will be

• A. 49 kPa
• B. 4.9 kPa
• C. 490 kPa
• D.
  0.49 kPa

Answer 1

The correct option is B 4.9 kPa

Pressure = $\frac{Thrust}{Area}$
Thrust = weight of cube = mass$\times$ g
g= 9.8 $m/s^2$
Area = $10\times 10\times {10}^{-4}{m}^2$
Pressure = $\frac{5\times 9.8}{{10}^{-2}}$ Pa
=4900Pa
=4.9 kPa