Question

A cylindrical block of wood is kept on a table. The mass of the block is $6.20\text{kg}$ and it is kept such that its one flat surface rests on the table. If the radius of the cylinder is $5\text{cm}$, then find the pressure exerted by the block on the table.

Take $g=10{\text{m/s}}^2$ and $\pi =3.14$

• A. $3920{\text{N/m}}^2$
• B. $7898{\text{N/m}}^2$
• C. $1960{\text{N/m}}^2$
• D. $2784{\text{N/m}}^2$

Answer 1

The correct option is B $7898{\text{N/m}}^2$



We know that, pressure,

$P=\frac{\text{Force}}{\text{Area}}=\frac{mg}{\pi r^2}=\frac{6.20\times 10}{3.14\times {0.05}^2}=7898{\text{N/m}}^2$