Question

A cube of side 0.2 m rest on the floor . Given that the cube has a mass of 50 kg. The pressure exerted by the cube on the floor is?

(Take $g=10N/kg$)

Answer 1

We know $F=ma$
Here force applied by the cube on the floor ($F$) = $50\times 10=500N$
Now area of the cube in contact with the surface
$A=0.2\times 0.2=0.04m^2$
Also pressure $\left(P\right)=\frac{F}{A}$
so here $P=\frac{500N}{0.04}{m}^2$
$P=12500Pa$.