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Question

A cube of side 100 mm is placed at the bottom of an empty container on one of its faces. The density of the material of the cube is 800 kg/ $m^{3}$ . Liquid of density 1000kg/ $m^{3}$ is now poured into the container. The minimum height to which the liquid needs to be poured into the container for the cube to just lift up is______mm.
80

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Solution

The correct option is A 80
To just lift the block from the bottom,
Weight of cube $= F_{B}$
$\Rightarrow ρ g \times V = ρ_{i} g \times \forall$
$\Rightarrow 800 \times a^{3} = 1000 \times a^{2} \times h$
$\Rightarrow h = 0.8 \times a$
$= 0.8 \times 100 = 80 m m$

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The correct option is A 80To just lift the block from the bottom, Weight of cube = FB ⇒ρg×V=ρig×∀ ⇒800×a3=1000×a2×h ⇒h=0.8×a =0.8×100=80mm

The correct option is A 80
To just lift the block from the bottom,
Weight of cube $= F_{B}$
$\Rightarrow ρ g \times V = ρ_{i} g \times \forall$
$\Rightarrow 800 \times a^{3} = 1000 \times a^{2} \times h$
$\Rightarrow h = 0.8 \times a$
$= 0.8 \times 100 = 80 m m$