Question

A cube painted red on two adjacent faces and black on the faces opposite to the red faces and green on the remaining faces is cut into 64 smaller cubes of equal size.

How many smaller cubes have less than three faces painted?

• A. $8$
• B. $24$
• C. $48$
• D. $56$

Answer 1

The correct option is D $56$

So we have to calculate all cubes less than 3 sides painted.
which means$=$(total no. of cubes) $-$(three sided painted cubes)
$=64-8$
$=56$
Hence, option 'D' is correct.