A cubical body of mass 5kg and side of length 20 cm is half immersed in a liquid .find the magnitude of upthrust on it.taking g=10m/s2

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Solution

Density of fluid is not given. Upthrust is equal to weight of fluid displaced.
Weight of fluid displaced= Volume of fluid immersed× density of fluid ×g
volume of fluid immersed= volume of liquid displaced. Here density od fluid is not given.

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A body of volume 100 $c m^{3}$ weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 $\times 10^{3} k g m^{- 3}$ . Find :
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State the assumption made in part (i).