A cubical container of side $3.5$ m is to be painted both inside and outside. Find the area to be painted and the total cost of painting it at the rate of Rs $75$ per square meter.

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Solution

T.S.A of cube $= 6 a^{2}$
$= 6 \times 3.5 \times 3.5$
$= 6 \times 12.25 = 73.5 m^{2}$
Since we have to paint inside and outside therefore total area $= 73.5 \times 2 = 147 m^{2}$
Now we know that cost of painting $= R s . 75$ per $m^{2}$
Cost of painting for $147 m^{2}$ $= 147 \times 75 = R s . 11025$

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A cubical container of side 3.5m is to be painted both inside and outside. Find the area to be painted and the total cost of painting it at the rate of Rs 75 per square meter.

T.S.A of cube =6a2 =6×3.5×3.5 =6×12.25=73.5m2Since we have to paint inside and outside therefore total area =73.5×2=147m2Now we know that cost of painting =Rs.75 per m2Cost of painting for 147m2 =147×75=Rs.11025

A cubical container of side $3.5$ m is to be painted both inside and outside. Find the area to be painted and the total cost of painting it at the rate of Rs $75$ per square meter.