A cubical Gaussian surfaces encloses $30 C$ per unit permittivity of charge. The electric flux through each face of the cube is

30 C

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15 C

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10 C

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5 C

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Solution

The correct option is B $5 C$
Given cube encloses $\frac{30 C}{ϵ_{o}}$
we know gauss law $\oint E \cdot d a = \frac{q_{o}}{ϵ_{o}}$
$∴$ Total flux through all 6 faces $= 30 C$ per unit permittivity
$\Rightarrow$ Flux through each face $= \frac{30}{6}$

$\Rightarrow \frac{5 C}{ϵ_{o}}$

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A cubical Gaussian surfaces encloses 30 C per unit permittivity of charge. The electric flux through each face of the cube is

The correct option is B 5 CGiven cube encloses 30Cϵowe know gauss law ∮E⋅da=qoϵo∴ Total flux through all 6 faces =30C per unit permittivity⇒ Flux through each face =306⇒5Cϵo

A cubical Gaussian surfaces encloses $30 C$ per unit permittivity of charge. The electric flux through each face of the cube is

The correct option is B $5 C$
Given cube encloses $\frac{30 C}{ϵ_{o}}$
we know gauss law $\oint E \cdot d a = \frac{q_{o}}{ϵ_{o}}$
$∴$ Total flux through all 6 faces $= 30 C$ per unit permittivity
$\Rightarrow$ Flux through each face $= \frac{30}{6}$

$\Rightarrow \frac{5 C}{ϵ_{o}}$