Question

A cubical tank of length 3m is filled with water of 2m depth. If the tank is accelerated horizontally at constant rate of 10 $m/se{c}^2$. Calculate the angle of free surface to the horizontal:

• A. ${30}^0$
• B. ${45}^0$
• C. ${60}^0$
• D. ${90}^0$

Answer 1

Answer: (B)

${45}^0$

Given,

$a=10m/s^2$

Take $g=10m/s^2$

The angle of free surface to the horizontal,

$tan\theta =\frac{a}{g}=\frac{10}{10}$

$tan\theta =1$

$\theta =ta{n}^{-1}\left(1\right)$

$\theta ={45}^0$

The correct option is B.