A current 3 A flows through 2 - resistor as shown in the circuit- The power dissipated in the 5 - resistor is

Since 3 A current flows through 2 Ω, so voltage across it is nbsp; V=iR = 3 × 2= 6 V Current through 5 Ω, i = 65+1 =1 A ∴ power dissipated in 5 Ω, P=i^2R=(i ...

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Standard X

Physics

Electrical Resistivity and Electrical Conductivity

A current 3 A...

Question

A current $3 A$ flows through $2 Ω$ resistor as shown in the circuit. The power dissipated in the $5 Ω$ resistor is

1 W

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5 W

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4 W

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2 W

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Solution

The correct option is B $5 W$
Since $3 A$ current flows through $2 Ω$ , so voltage across it is
$V = i R = 3 \times 2 = 6 V$
Current through $5 Ω, i = \frac{6}{5 + 1} = 1 A$
$∴$ power dissipated in $5 Ω$ ,
$P = i^{2} R = (i)^{2} \times 5 = 5 W$

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A current 3 A flows through 2 Ω resistor as shown in the circuit. The power dissipated in the 5 Ω resistor is

The correct option is B 5 WSince 3 A current flows through 2 Ω, so voltage across it is V=iR=3×2=6 V Current through 5 Ω,i=65+1=1 A ∴ power dissipated in 5 Ω, P=i2R=(i)2×5=5 W

A current $3 A$ flows through $2 Ω$ resistor as shown in the circuit. The power dissipated in the $5 Ω$ resistor is

The correct option is B $5 W$
Since $3 A$ current flows through $2 Ω$ , so voltage across it is
$V = i R = 3 \times 2 = 6 V$
Current through $5 Ω, i = \frac{6}{5 + 1} = 1 A$
$∴$ power dissipated in $5 Ω$ ,
$P = i^{2} R = (i)^{2} \times 5 = 5 W$