Question

A current of 0.1 A flows through a 25 $\Omega$ resistor represented by the circuit diagram. The current in the 80 $\Omega$ resistor is

• A. 0.1 A
• B. 0.2 A
• C. 0.3 A
• D. 0.4 A

Answer 1

The correct option is C 0.3 A

Total resistance along 0.1 A

$\frac{1}{R}=\frac{1}{20}+\frac{1}{60}$

$R=15\Omega$

Total resistance$=15+25=40\Omega$

Now the current distribute inverse to resistance

$\frac{0.1}{I}=\frac{20}{40}$

$I=0.2A$

Total current through $80\Omega =0.1+0.2=0.3A$