Question

A current carrying coil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth's magnetic field be $H_0$ and magnetic field inside the loop is H. If a magnet issue suspended inside the loop, it makes angle $\theta$ with

• A. ${\tan }^{-1}\left(\frac{H_0}{H}\right)$
• B. ${\tan }^{-1}\left(\frac{H}{H_0}\right)$
• C. ${\csc }^{-1}\left(\frac{H}{H_0}\right)$
• D. ${\cot }^{-1}\left(\frac{H_0}{H}\right)$

Answer 1

The correct option is A ${\tan }^{-1}\left(\frac{H_0}{H}\right)$

$\text{Given:-}$ horizontal component of earth's magnetic field be $H_o$ and magnetic field inside the loop is H.

$\text{To find:-}$angle $\theta$

$\text{Solution:-}$

In given case $H$ and $H_o$ are perpendicular to each other.

Therefore, $tan\theta =H_0/H$

This implies,

$\theta =ta{n}^{-1}{H}_0/H$

$\text{Hence the correct option is A}$