A current I flows in the anticlockwise direction through a square loop of side a lying in the xoy plane with its center at the origin. The magnetic induction at the center of the square loop is
A
2√2μ0Iπa^ex
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B
2√2μ0Iπa^ez
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C
2√2μ0Iπa2^ez
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D
2√2μ0Iπa2^ex
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Solution
The correct option is B2√2μ0Iπa^ez Field due to one side of loop at O =4.μI4π(a2)(2sin450) Field at O due to all four sides is along unit vector ¯ez ∴ Total field =4.μI4π(a2)(2sin450)=2√2μ0Iπa