A current I flows through a flat metal specimen of constant thickness and of the shape as shown in the figure. Given that v1,v2 and v3 are mean drift speeds of the electron crossing the sections P1,P2 and P3 respectively. Then
A
v2<v1<v3
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B
v1<v2<v3
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C
v1=v3<v2
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D
v1>v2=v3
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Solution
The correct option is Av2<v1<v3 From the relation of electric current and drift velocity, we know that I=neAv=ne(wt)v∵(A=wt) ⇒v∝1w w=width, other symbols have usual meaning. ∴ Greater the width of the section, lesser will be the drift velocity and vice-versa. ⇒v2<v1<v3