Question

# A current loop of area $0.01{m}^{2}$and carrying a current of $100A$is held parallel to a magnetic field of intensity $0.1T$. The torque in $Nm$ acting on the loop is:

A

$Zero$

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B

$0.01Nm$

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C

$0.001Nm$

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D

$0.8Nm$

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Solution

## The correct option is A $Zero$Step 1: Given dataArea of the current loop, $A=0.01{m}^{2}$Electric current flowing in the current loop, $I=100A$Magnetic field intensity, $B=0.1T$Angle between the current loop and the magnetic field, $\theta ={0}^{0}$Torque acting on the current loop, $𝜏=?$Step 2: Formula used$𝜏=IAB\mathrm{sin}\theta$ ………………….(a)Step 3: Calculation of the torque acting on the current-carrying loopSubstituting the given values in equation (a), we get$𝜏=100A×0.01{m}^{2}×0.1T×\mathrm{sin}{0}^{0}\phantom{\rule{0ex}{0ex}}𝜏=100×0.01×0.1×0\phantom{\rule{0ex}{0ex}}𝜏=0$Hence, option (a) is correct.

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