A current of $0.1 A$ circulates around a coil of $100$ turns and having a radius equal to $5 cm$ . The magnetic field set up at the centre of the coil is
( $μ_{0} = 4 π \times 10^{- 7} weber/ampere-metre$ )

4 π \times 10^{- 5} tesla

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8 π \times 10^{- 5} tesla

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4 \times 10^{- 5} tesla

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2 \times 10^{- 5} tesla

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Solution

The correct option is A $4 π \times 10^{- 5} tesla$
$B = \frac{μ_{0} N i}{2 r} = \frac{4 π \times 10^{- 7} \times 100 \times 0.1}{2 \times 5 \times 10^{- 2}}$
$= 4 π \times 10^{- 5} Tesla$

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Q. A current of

0.1 A

circulates around a coil of

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μ_{0} = 4 π \times 10^{- 7} weber/ampere-metre

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A current of 0.1 A circulates around a coil of 100 turns and having a radius equal to 5 cm. The magnetic field set up at the centre of the coil is (μ0=4π×10−7 weber/ampere-metre)

The correct option is A 4π×10−5 teslaB=μ0Ni2r=4π×10−7×100×0.12×5×10−2 =4π×10−5 Tesla

A current of $0.1 A$ circulates around a coil of $100$ turns and having a radius equal to $5 cm$ . The magnetic field set up at the centre of the coil is
( $μ_{0} = 4 π \times 10^{- 7} weber/ampere-metre$ )

The correct option is A $4 π \times 10^{- 5} tesla$
$B = \frac{μ_{0} N i}{2 r} = \frac{4 π \times 10^{- 7} \times 100 \times 0.1}{2 \times 5 \times 10^{- 2}}$
$= 4 π \times 10^{- 5} Tesla$