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Question

# A current of 1 A is drawn by a filament of an electric bulb. What will be the approximate number of electrons passing through a cross section of its filament in 16 seconds?

A
1020
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B
1019
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C
1022
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D
1023
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Solution

## The correct option is A 1020Given: Current, I=1 A t=16 s Since, I=Qt Where Q is the total charge passing through a cross-sectional area. Hence, 1 A=Q(16 s) Q=16 C Also, charge of an electron, e=1.6×10−19C Let the no. of electrons be n. Then, I×t=Q=n×e n=1×161.6×10−19 n=1020electrons.

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