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Question

A current of 1 A is drawn by a filament of an electric bulb. What will be the approximate number of electrons passing through a cross section of its filament in 16 seconds?

A
1020
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B
1019
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C
1022
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D
1023
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Solution

The correct option is A 1020
Given:
Current, I=1 A
t=16 s
Since, I=Qt
Where Q is the total charge passing through a cross-sectional area.
Hence,
1 A=Q(16 s)
Q=16 C
Also, charge of an electron,
e=1.6×1019C
Let the no. of electrons be n. Then, I×t=Q=n×e
n=1×161.6×1019
n=1020electrons.

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