Question

A current of 16A flows through molten NaCI for 10 minutes. The amount of metallic sodium that appears at the negative electrode would be $($Faraday constant $=9.65\times {10}^4$ C$)$

• A. 11.5 gm
• B. 2.3 gm
• C. 1.15 gm
• D. 0.23 gm

Answer 1

The correct option is B 2.3 gm

The charge of $9.65\times {10}^{4}C$ liberates 23 g of Na. Hence, 16 A current for 10 min i.e. 600 s will liberate m gm(say), given by
$m=\frac{ZIt}{F}$

$m=\frac{23\times 16\times 600}{9.65\times {10}^4}=2.3g$.