A current of 2A flows in an electric circuit as shown in figure. The potential difference (VR−VS), in volts (VR and VS are potentials at R and S respectively) is:
A
−4
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B
+2
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C
+4
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D
−2
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Solution
The correct option is C+4 Current through each arm PRQ and PSQ=1A VP−VR=3V ...(i) VP−VS=7V ...(ii) From equations (i) and (ii), we get VR−VS=+4V