A current of 2A is increasing at a rate of 4A/s through a coil of inductance 1H. Find the energy stored in the inductor per unit time in the units of J/s.
A
8
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B
2
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C
4
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D
6
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Solution
The correct option is A8 Power supplied to the inductor is P=Lididt Energy stored in inductor is E=Pt Energy stored in inductor per unit time is Et=P=Lididt=1×2×4=8Js−1