Question

A current of 3 A flows through the $2\Omega$ resistor shown in the circuit. The power dissipated in the $5\Omega$ resistor is :

• A. 4 W
• B. 2 W
• C. 1 W
• D. 5 W

Answer 1

The correct option is D 5 W

Voltage across $2\Omega$ resistance.
$2\times 3=6V$
So, voltage across lowest arm
$V_1=6V$
Current across $5\Omega ,/=\frac{6}{1+5}=1A$
Thus, power across $5\Omega$
$P=I^{2}R=(1{)}^2\times 5=5W$