A current of 3 amp. flows through the 2 ohm resistor shown in the circuit. The power dissipated in the 5 ohm resistor is:
Current in 2Ω resister = 3A
Potential across 2Ω resister V= IR=3×2=6V
Potential is equal in parallel connection.
Current flow in 1Ω & 5Ω resister i=VR= 65+1=1A
Power dissipate in 5Ω resister =i2R=12×5=5 W
Power dissipate in 5Ω resister is 5W