Question

A current of $3A$ is flowing in a linear conductor having a length of $40cm$. The conductor It is placed in a magnetic field of strength $500$ gauss and makes an angle of ${30}^o$ with the direction of the field. It experience a force of magnitude $n\times {10}^{-2}N$. Find the value of $n$

Answer 1

Force on a current carrying conductor is given as $F=ILBsin\theta$ where $\theta$ is angle between length $L$ and field $B$. i.e. ${30}^0$

Put $B=500\times {10}^{-4}Tesla$ and $L=0.4m$ with $I=3A$ we get

$F=3\times {10}^{-2}N$ so $n=3$