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Question

A current of 5 A is passing through a metallic wire of cross-sectional area 4×106m2. If the density of charge carriers of the wire is 5×1026m3, then the drift velocity of the electrons will be

A
1×102m/s
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B
1.56×102m/s
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C
1.56×103m/s
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D
1×102m/s
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Solution

The correct option is B 1.56×102m/s
Given : n=5×1026m3,A=4×106m2,I=5A,e=1.6×1019C

Step 1 : Use the formula for drift velocity
Drift velocity, v=InAe .......(1)

Step 2 : Substitute the values in equation (1)
v=5A(4×106m2)×(5×1026m3)×(1.6×1019C)=1.56×102m/s

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